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Balance the following equations in acidic medium by both oxidation number and ion electron methods and identify the oxidants and the reductants. H2S + Cl2 ----->S + Cl- |
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Answer» MnO 4− +C 2 H 2 O 4 ⇌Mn 2 +CO 2 +H 2 OMn+7 O−2 4− + C 2 +3 H 2 +1 O 4 −2 ⇌ Mn 2 0 + C+4 O 2 −2 + H 2 + O−2 Oxidation: C 2 +3 H 2 1 O 4 −2 ⟶ C+4 O 2 −2 Rediuction: Mn+7 O 4− −2 ⟶ Mn 2 0 Balancing on both sides;O:C 2 H 2 O 4 ⟶2CO 2 +2H + R:2MnO 4− ⟶Mn 2 +8H 2 O⇒O:C 2 H 2 O 4 ⟶2CO 2 +2H + +2e − R:14e − +2MnO 4− +16H + ⟶Mn 2 +8H 2 O__________________________________________7C 2 H 2 O 4 ⟶14CO 2 +14H + +14e − 2MnO 4− +16H + +14e − ⟶Mn 2 +8H 2 O⇒7C 2 H 2 O 4 +2MnO 4− +16H + +14e − ⇌14CO 2 +MN 2 +14H + +8H 2 O+14e − |
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