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Balance the following ionic equation. MnO_(4)^(-)+H^(+)+Br^(-)toMn^(2+)+Br_(2)+H_(2)O |
Answer» Solution :Write the O.N. of all TEH atoms above their respective symbols <BR>  Divide skeleton equation into two half reactions. Reduction half reaction `MnO_(4)^(-)toMn^(2+)` OXIDATION half reaction `Br^(-)toBr_(2)` To balance reduction half reaction `MnO_(4)^(-)+8H^(+)+5e^(-)toMn^(2+)+4H_(2)O` To balance oxidation half reaction `2Br^(-)toBr_(2)+2e^(-)` To balance the reaction `({:(2MnO_(4)^(-)+16H^(+)+10E^(-)to2Mn^(2+)+8H_(2)O),(""10Br^(-)to5Br_(2)+10e^(-)):})/(2MnO_(4)^(-)+10Br^(-)+16H^(+)to2Mn^(2+)+5Br_(2)+8H_(2)O)` This represent the correct balanced ionic equation |
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