Balance the following reaction by the oxidation number method - `MnO_(

1.	Balance the following reaction by the oxidation number method - `MnO_(4)^(-)+Fe^(+2)rarrMn^(+2)+Fe^(+3)`
Answer» Write the oxidation number of all the atoms. `overset(+7-2)(MnO_(4)^(-))+" "Fe^(+2)rarrMn^(+2)+Fe^(+3)` Change in oxidation number has occurred in Mn and Fe. `{:(overset(+7)(MnO_(4)^(-))rarroverset(+2)(Mn^(+2))," ..................(1) (Decrement in oxidation number by 5)"),(Fe^(+2)rarrFe^(+3)," ..................(2) (Increment in oxidation number by 1)"):}` To make increase and decrease equal, eq. (2) is multiplied by 5. `MnO_(4)^(-)+5Fe^(+2)rarrMn^(+2)+5Fe^(+3)` To balance oxygen, `4H_(2)O` are added to R.H.S. and to balance hydrogen, `8H^(+)` are added to L.H.S. `MnO_(4)^(-)+5Fe^(+2)+8H^(+)rarrMn^(+2)+5Fe^(+3)+4H_(2)O` This is the balanced equation.

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Balance the following reaction by the oxidation number method - `MnO_(4)^(-)+Fe^(+2)rarrMn^(+2)+Fe^(+3)`

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