Balance the following redox reaction by half reaction method. Fe^(2+)(aq)+Cr_(2)O_(7)^(2-)(aq)toFe^(3+)(aq)+Cr^(3+)(aq) (In acid medium)

Balance the following redox reaction by half reaction method. Fe^(2+)(

1.	Balance the following redox reaction by half reaction method. Fe^(2+)(aq)+Cr_(2)O_(7)^(2-)(aq)toFe^(3+)(aq)+Cr^(3+)(aq) (In acid medium)
Answer» Solution :STEP 1: (LEO= Loss of Electron Oxidation) (GER= Gain of Electron Reduction) Step 2: `Fe^(2+)+Fe^(3+).....(1)(2to3=1 unitON)` `Cr_2O_7^(2-)to2Cr^(3+)....(2)(+6to+3=3 units 2 sets IMPLIES 6 units ON)` Step 3: Cross Multiplication i.e., (1) `times`6 and (2) `times` 1 `(1)times6to6Fe^(2+)to6Fe^(3+)......(3)` `(2)times1toCr_2O_7^2to2Cr^(3+).....(4)` Step 4: Add (3)+(4) `to6Fe^(2+)+CrO_7^(2-)to 6FE^(3+)+2Cr^(3+)` Step 5: Balance oxygen and then hydrogen `6Fe^(2+)+CrO_7^(2-)+14H^(+) to 6Fe^(3+)+2Cr^(3+)+7H_2O`