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Balance the following redox reactions by ion -electron method: H_(2)O_(2)(aq)+Fe^(2+)(aq) to Fe^(3+)(aq)+H_(2)O(l)(in acidic solution) |
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Answer» SOLUTION :Oxidation reaction : `Fe^(2+)(aq)toF^(3+)(aq)+e` Reduction reaction:`H_(2)O_(2)(aq)+2H^(+)_(2)O(l)` Multipying equation (1) and (2) then ADDING it to equation (2), we have `2Fe^(2+)(aq)+H_(2)O_(2)(aq)+2H^(+)(aq)2Fe^(3+)(aq)+2H_(2)O(l)` |
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