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Ball 1 collides with an another identical ball 2 at rest as shown in figure. For what value of coefficient of restitution e, the velocity of second ball becomes two times that of 1 after collision ? |
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Answer» SOLUTION :Here `m_(1) = m_(2) and u_(2) = 0`. After collision, `v_(2) = ((1+c)/(2)) u and v_(1) = ((1-e)/(2))u` GIVEN , `v_(2) = 2v_(1)` on solving we GET, `e = (1)/(3)` |
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