Ball 1 collides with an another identical ball 2 at rest as shown in figure. For what value of coefficient of restitution e, the velocity of ball 2 becomes two times that of ball I after collision?

Ball 1 collides with an another identical ball 2 at rest as shown in f

1.	Ball 1 collides with an another identical ball 2 at rest as shown in figure. For what value of coefficient of restitution e, the velocity of ball 2 becomes two times that of ball I after collision?
Answer» `1/3` `1/2` `1/4` `1/6` SOLUTION :LET U be the initial velocity of ball 1. Then , after collision `v_1 = ((1 - e)/(2)) u and v_2 = ((1 +e)/(2)) u :. (v_2)/(v_1) = (1 + e)/(1 - e)` But `v_2 = 2v_1` (given ) `:. 2 = (1 + e)/(1 - e)` On solving, we GET `e = 1/3`.