1.

[bar(a)xx bar(b)" "bar(a)xx bar( c )" "bar(d)] = …………….

Answer»

`(BAR(a)*bar(d))[bar(a)bar(B)bar( C )]`
`(bar(a)*bar( c ))[bar(a)bar(b)bar( c )]`
`(bar(a)*bar(b))[bar(a)bar(b)bar( c )]`
NONE of these

ANSWER :A


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