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bar(d)=lambda(bar(a)xx bar(b))+mu(bar(b)xx bar( c ))+v(bar( c )xx bar(a)) and [bar(a)bar(b)bar( c )]=(1)/(8) then lambda+mu+v = ………….. |
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Answer» `bar(d)*(bar(a)+bar(B)+bar( C ))` |
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