Based on equation `E = -2.178 xx 10^-18 J((Z^2)/(n^2))`, certain conclusions are written. Which of them is not correct ?A. The large the value of `n`, the large is the orbit radius.B. The eqaution can be used to calculate the change in enegry when the electrons change orbit.C. For `n = 1`, the electron has more negative energy tham it does for `n = 6` which means that the electron is more lossely bound in the smallest allowed orbit.D. The negative sign in equation means that the enegry of the electron bound to the nucleus is lower than it would be if the electrons were at infinite distance form the nucleus.

Based on equation `E = -2.178 xx 10^-18 J((Z^2)/(n^2))`, certain concl

1.	Based on equation `E = -2.178 xx 10^-18 J((Z^2)/(n^2))`, certain conclusions are written. Which of them is not correct ?A. The large the value of `n`, the large is the orbit radius.B. The eqaution can be used to calculate the change in enegry when the electrons change orbit.C. For `n = 1`, the electron has more negative energy tham it does for `n = 6` which means that the electron is more lossely bound in the smallest allowed orbit.D. The negative sign in equation means that the enegry of the electron bound to the nucleus is lower than it would be if the electrons were at infinite distance form the nucleus.
Answer» Correct Answer - C More nagative enegry implies that the electron is closer to the nucleus and thus, more strongly bound to the nucleus. `(1)` Size of the orbit is directly related to the value of principal quantum number. (2)` DeltaE = E_(f) - E_(i)` `=- 2.1789 xx 10^(-18)JZ^(2) ((1)/(n_(f)^(2))-(1)/(n_(f)^(2)))` `(4)` At infinite distance form the nucleus, the enegry of electronb is taken to be zero.

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