1.

Based on first law of thermodynamics , which one of the following is correct ?

Answer»

For an isochoric proces`,DeltaU =-q`
For an ADIABATIC PROCESS, `DeltaU = -W`
For an isothermal process`,q= +w`
For a cyclic process,`q= -w`

Solution :(a) `DeltaU = q+w`. For an isochoric process,`w = - P DeltaV =0`. Hence,`DeltaU = q_(v)`
(b) For an adiabatic process , `q=0`. Hence, `DeltaU =w`
(C ) For an isothermal process, `DeltaU =0` Hence, `q=-w`
(d) For a cyclic process, `DeltaU =0`. Hence, `q= - w`


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