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Based on reductive ozonolysis reaction, how do you distinguish between an alkene and alkyne? |
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Answer» SOLUTION :An alkene, on reductive ozonolysis TWO carbonyl COMPOUNDS are formed. `R-CH=CH-R.underset((ii)H_(2)OZn)overset((i)O_(3))toR-CHO+R.CHO` An alkyne, on reductive ozonolysis, a dicarbonyl COMPOUND is formed. `R-C-=C-R.underset((ii)H_(2)O,Zn)overset((i)O_(3))toR-underset(O)underset(||)C-underset(O)underset(||)C-R.` |
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