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Based on the Bohr model, what is the minimum energy required to remove an electron from the ground state of Be atom? (Given: Z = 4)(a) 1.63 eV(b) 15.87 eV(c) 30.9 eV(d) 217.6 eVI have been asked this question during an internship interview.This interesting question is from Alpha-Particle Scattering and Rutherford’s Nuclear Model of Atom topic in portion Atoms of Physics – Class 12

Answer» RIGHT answer is (d) 217.6 eV

To elaborate: The equation is given as:

En = \(\frac {-13.6 Z^2}{n^2}\) eV

En = \(\frac {-13.6 \times 16 }{ 1 }\)

En = -217.6 eV

Hence the ionization ENERGY for an electron in the GROUND state of Be ATOM is 217.6 eV.


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