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What is the ratio of minimum to maximum wavelength in the Balmer series?(a) 5:9(b) 5:36(c) 1:4(d) 3:4I had been asked this question in an interview.I need to ask this question from Atomic Spectra topic in chapter Atoms of Physics – Class 12

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Right OPTION is (a) 5:9

To explain I would SAY: For a wavelength of BALMER series,

\(\frac {1}{\lambda }\) = R\( [ \frac {1}{4} – \frac {1}{9} ] \)

\(\frac {1}{\lambda } = \frac {5R}{30}\).

\(\frac {\lambda_{min}}{\lambda_{MAX}} = \frac {5R}{36} \times \frac {4}{R} \)

\(\frac {\lambda_{min}}{\lambda_{max}} = \frac {5}{9}\)



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