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BD and CE are median of ∆ ABC. Prove that:area( ∆GBC)area(AEGD). |
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Answer» (i) Since, BD and CE are medians. AD = DC AE = BE Hence, by converse of Basic Proportionality theorem, ED || BC In ΔEGD and ΔCGB, ∠DEG = ∠GCB (alternate angles) ∠EGD = ∠BGC (Vertically opposite angles) ΔEGD ~ ΔCGB (AA similarity) |
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