BE ACDE = BC18, in Fig. 1, DB-L BC, DE LA B and ACä¸BC. Prove that

1.	BE ACDE = BC18, in Fig. 1, DB-L BC, DE LA B and ACä¸BC. Prove thatFig. 1
Answer» In the triangle DEB and triangle ACD. angle DEB=Angle ABC anlge DEB = angle ACD (each is of 90) therefore we can easily say that triangle DEB= triangle ACB ( according to AA rule) Hence BE/BC =AC/DEAnd then now we can have BE/DE = AC/BE

BE ACDE = BC18, in Fig. 1, DB-L BC, DE LA B and ACä¸BC. Prove thatFig. 1

Answer»

In the triangle DEB and triangle ACD.

angle DEB=Angle ABC

anlge DEB = angle ACD (each is of 90)

therefore we can easily say that triangle DEB= triangle ACB ( according to AA rule)

Hence BE/BC =AC/DEAnd then now we can have BE/DE = AC/BE