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BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles. |
Answer» BE=CF `angleBEC=angleCFB=90^0` In `/_BFC and /_CEB` `angleBEC=angleCFB=90^0` BC=BC BE=CF `/_BFCcong/_CEB` `angleFBC=angleECB` In `/_ABC and angleACB=angleABC`----> isosceles AB=AC. |
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