1.

BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.

Answer» BE=CF
`angleBEC=angleCFB=90^0`
In `/_BFC and /_CEB`
`angleBEC=angleCFB=90^0`
BC=BC
BE=CF
`/_BFCcong/_CEB`
`angleFBC=angleECB`
In `/_ABC and angleACB=angleABC`----> isosceles
AB=AC.


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