1.

Be reacts with excess of caustic soda to form

Answer»

`Be(OH)_(2)`
`BeO`
`Na_(2)[Be(OH)_(4)]`
`Be(OH)_(2).BeCO_(3)`

Solution :`Be(OH)_(2)+2NAOH to Na_(2)[Be(OH)_(4)]`
`Be(OH)_(2)*BeCO_(3)`


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