1.

BeC+4H_(2)O to Be(OH)_(2)+CH_(4) CaC_(2)+2H_(2)O to Ca(OH)_(2)+X Mg_(2)C_(3)+2H_(2)O to Mg (OH)_(2)+Y The total no. of pi bonds present in X and Y

Answer»


SOLUTION :`Be_(2)C+4H_(2)O to Be(OH)_(2)+CH_(4)`,
`CaC_(2)+2H_(2)OtoCa(OH)_(2)+H-Cunderset(X)(-=)C-H`
`Mg_(2)C_(3)+2H_(2)O to mg(OH)_(2)+CH_(2)underset(X)(-)C-=C-H`
`ul{:(x"has" 2pi"bonds"),(Y "has" 2pi "bonds"),("TOTAL" 4PI "bonds"):}`


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