1.

BeCI_(2)+LiAIH_(4)rarrX-LiCI +AICI_(3)

Answer»

X is LiH
X is `BeH_(2)`
X is `BeCI_(2)2H_(2)O`
None

Solution :`2BeCi_(2) + LiAIH_(4) rarr 2BeH_(2) + LICI + AICI_(3)`


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