1.

Becomes 72 kmh in 15 seconds. FinaQS- A bus staring from rest accelerates in a straight line at a constant rate of 3ms 2 for 3 seconds. Calculate the distance travelled by the bus during this timeinterval.​

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ANSWER:

here is your answer

given DATA :

initial velocity (u) = 0

acceleration (a) = 3 m/s²

time (t) = 8 seconds

to find : distance travelled

here we go

solution :

by using 2nd EQUATION of motion

s = ut+1/2at²

s = 0+1/2*3*(8)²

s = 96 meter

hope it helps :)

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