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Becomes 72 kmh in 15 seconds. FinaQS- A bus staring from rest accelerates in a straight line at a constant rate of 3ms 2 for 3 seconds. Calculate the distance travelled by the bus during this timeinterval. |
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Answer» here is your answer given DATA : initial velocity (u) = 0 acceleration (a) = 3 m/s² time (t) = 8 seconds to find : distance travelled here we go solution : by using 2nd EQUATION of motion s = ut+1/2at² s = 0+1/2*3*(8)² s = 96 meter hope it helps :) READ more on Brainly.in - brainly.in/question/3971964#readmore |
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