BED || EF ,(ANGLE) AEF=55° and (ANGLE )ACB= 25 ° , FIND (ANGLE )ABC

1.	BED \|\| EF ,(ANGLE) AEF=55° and (ANGLE )ACB= 25 ° , FIND (ANGLE )ABC
Answer» ∠FEA = ∠EABtherfore ∠EAB = 55°therfore ∠CAB = 180° -55°∠CAB=125therfore\xa0∠ABC = 180° - 25 °- 125° ( angle sum property )∠ABC = 30° degree

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