\begin{array}{c}{\sqrt{12 \sqrt{12 \sqrt{12}}} \ldots-x} \\ {x=?}\end{ – InterviewSolution

1.	\begin{array}{c}{\sqrt{12 \sqrt{12 \sqrt{12}}} \ldots-x} \\ {x=?}\end{array}
Answer» root(12root(12root(12.....)))=xroot(12 × x)=xby taking square both the sides12x=x^2x^2-12x=0x(x-12)=0x=0 or 12

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