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\begin{array}{l}{\text { (i) } \tan 48^{\circ} \tan 23^{\circ} \tan 42^{\circ} \tan 67^{\circ}-1} \\ {\cos 38^{\circ} \cos 52^{\circ}-\sin 38^{\circ} \sin 52^{\circ}-0}\end{array} |
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Answer» tan 48 cot 23 tan 42 cot 421*1=1since cot A. tan A=1 |
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