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\begin{array} { l } { \text { In a division sum, the remainder is } 0 \text { . As } } \\ { \text { student. mistook the divisor by } 12 \text { instead of } } \\ { 21 \text { and obtained } 35 \text { as quotient. What is the } } \\ { \text { correct quotient? } } \\ { \text { (a) } 0 } \\ { \text { (c) } 13 \text { . } } \end{array} |
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Answer» division algorithma = bq + ra = 12×35 a = 21p so21p = 12×35p = (12×35)/21 = (12 ×5)/3 = 4×5p = 20d) is correct option |
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