InterviewSolution
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InterviewSolution
| 1. |
\begin{array} { l } { \text { Solve for } x : } \\ { \left( \frac { 4 x - 3 } { 2 x + 1 } \right) - 10 \left( \frac { 2 x + 1 } { 4 x - 3 } \right) = 3 , x \neq - \frac { 1 } { 2 } , \frac { 3 } { 4 } } \end{array} |
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