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\begin{array}{l}{\text { Solve for } x \text { and } y, \text { given that }} \\ {\left[ \begin{array}{cc}{3} & {-4} \\ {1} & {2}\end{array}\right] \left[ \begin{array}{l}{x} \\ {y}\end{array}\right]=\left[ \begin{array}{c}{3} \\ {11}\end{array}\right]}\end{array} |
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Answer» 3x-4y=3x+2y=113x-4y+2x+4y=3+22=255x=25so x=515-4y=34y=12y=3 |
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