Saved Bookmarks
| 1. |
\(\begin{bmatrix}0 & -3 & 1\\2 & -1 & 1\\2 & -1 & 1\end{bmatrix}\)\(\begin{bmatrix}0 & -1 & 1\\0 & 1 & -1\\0 & 3 & -3\end{bmatrix}=\)[0, -3, 1][2, -1, 1][2, -1, 1] [0, -1, 1][0, 1, -1][0, 3, -3] =(A) \(\begin{bmatrix}0 & 1 & 0\\0 & 0 & 1\\1 & 0 & 0\end{bmatrix}\)(B) \(\begin{bmatrix}1 & 1 & 1\\1 & 1 & 1\\1 & 1 & 1\end{bmatrix}\)(C) \(\begin{bmatrix}0 & 3 & 7\\1 & 1 & 1\\3 & -1 & 7\end{bmatrix}\)(D) \(\begin{bmatrix}0 & 0 & 0\\0 & 0 & 0\\0 & 0 & 0\end{bmatrix}\) |
|
Answer» Correct answer is (D) \(\begin{bmatrix}0 & 0 & 0\\0 & 0 & 0\\0 & 0 & 0\end{bmatrix}\) |
|