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\(\begin{bmatrix}-3 & 9 \\-13 & -1 \\\end{bmatrix}\)\(\begin{bmatrix}1 & 0 \\0 & 1 \\\end{bmatrix}=\)[-3, 9][-13, -1][1, 0][0, 1] =(A) \(\begin{bmatrix}-3 & 0 \\0 & -1 \\\end{bmatrix}\)(B) \(\begin{bmatrix}-2 & 9 \\-13 & -1 \\\end{bmatrix}\)(C) \(\begin{bmatrix}-3 & 9 \\-13 & -1 \\\end{bmatrix}\)(D) \(\begin{bmatrix}1 & 0 \\0 & 1 \\\end{bmatrix}\) |
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Answer» Correct answer is (C) \(\begin{bmatrix}-3 & 9 \\-13 & -1 \\\end{bmatrix}\) |
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