Benzene burns in oxygen according to the equation 2C_(6)H_(6(l))+15O_(2(g))rarr12CO_(2(g))+6H_(2)O_((l)). How many litres of oxygen are required at STP for the complete combustion of 39g of liquid benzene?

Benzene burns in oxygen according to the equation 2C_(6)H_(6(l))+15O_(

1.	Benzene burns in oxygen according to the equation 2C_(6)H_(6(l))+15O_(2(g))rarr12CO_(2(g))+6H_(2)O_((l)). How many litres of oxygen are required at STP for the complete combustion of 39g of liquid benzene?
Answer» `11.2` `22.4` 42 84 Solution :`39g=(1)/(2)` MOLE IMPLIES moles of `O_(2)=(15)/(4)` implies VOLUME = `(15)/(4)xx22.4=84`