Benzene, ethane and ethylene belong to the family of hydrocarbons. Show how the data given below is in consistent with the law of Multiple Proportions. {:("Compound",underset("in 5.0 g of the sample")("Mass of carbon"),underset("in 5.0 g of the sample")("Mass of hydrogen")),("Benzene","4.61 g","0.39 g"),("Ethane","4.00 g","1.00 g"),("Ethylene","4.29 g","0.71 g"):} .

Benzene, ethane and ethylene belong to the family of hydrocarbons. Sho

1.	Benzene, ethane and ethylene belong to the family of hydrocarbons. Show how the data given below is in consistent with the law of Multiple Proportions. {:("Compound",underset("in 5.0 g of the sample")("Mass of carbon"),underset("in 5.0 g of the sample")("Mass of hydrogen")),("Benzene","4.61 g","0.39 g"),("Ethane","4.00 g","1.00 g"),("Ethylene","4.29 g","0.71 g"):} .
Answer» Solution :Let 1 g of hydrogen be the fixed MASS of hydrogen In benzene : 1.00 g of hydrogen are combined with carbon = 4.61 g 1.00 g of hydrogen are combined with carbon `= ((4.61g))/((0.39g))xx(1.0g)=11.82g` In ethane : 1.00 g of hydrogen are combined with carbon = 4.00 g In ethylene : 0.71 g of hydrogen are combined carbon = 4.29 g 1.00 g of hydrogen are combined with carbon `= ((4.29g))/((0.71g))xx(1g)=6.04g` Ratio by mass of carbon combined with 1 g of hydrogen in the three samples `11 : 82 : : 4.00 : 6.04 ::6 : 2 : 3` Since it is a simple whole number ratio, the LAW of MULTIPLE Proportions is obeyed.