InterviewSolution
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InterviewSolution
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Biprism experiment is conducted with a wavelength of `5000Å`. The distance between the virtual sources is 0.2 mm and the micrometer eyepiece is at a distance of 100 cm from the slits. The distance between the consecutive bright and dark between the consecutive bright and dark band isA. `1.25 mm`B. `2.5 mm`C. `3.5 mm`D. `0.25 mm` |
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Answer» Correct Answer - A `lambda 5000A^(@), d=0.2 mm D=1 m, beta = ?` `beta =(D)/(d) lambda` `=(1xx5xx10^(-7))/(0.2xx10^(-3))` `25xx10^(-4)` `=2.5 mm` b Thus distance between consecutive bright and dark band is `(beta)/(2)=(2.5)/(2)=1.25 mm` |
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