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Bismuth (V) is a stronger oxidising agent than Sb (V). Explain. |
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Answer» Solution :Due to inert pair effect, the stabilityof +5 oxisdation STATES decresase down the group, i.e., +5 OXIDATION state of Sb is more stable than +5 oxideation state of Bi. Thus, `Bi^(5+)` has a higher tendency to accept a pair of elections than `Sb^(5+)` i.e., `Bi^(5+)+2e^(-)toBi^(3+)`, higher tendency to accept ELECTRONS , stronger oxidising agent `Sb^(5+)+2e^(_)toSb^(3+),` LOWER tendancy to accept electrons , weakder oxidising agent In other words, Bi (V) is a stronger oxidising agent than Sb (V). |
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