1.

Block A has a mass of 30 kg and block B a mass of 15 kg . The coefficient of friction between all surface of contact are mu_(s) = 0.15 and mu_(s) = 0.10 Knowing that theta = 30^(@) and that the magnitude of the force F applied to block A is 250 N Determine (a) acceleration of block A and (b) the tension in the rope

Answer»


Solution :`m_(A)g SIN theta + F - T - f = m_(A) alpha`…(i)

` f = mu_(k) m_(A) g COS theta`….(ii)
`T - m_(B) sin theta - F - f' = m_(B) alpha`..(iii)
`f' = mu_(k) .N'`…(iv)
`= mu_(k) (m_(A) g cos theta + m_(B)g cos theta)`
Solving above EQUATION `a_(A) = 5.2 ms^(-2), T = 215 N`


Discussion

No Comment Found