1.

Block B moves to the right with a constant velocity v_(0). The velocity of body A relative to B is

Answer»

`(v_(0))/(2)`, towards LEFT
`(v_(0))/(2)`, towards right
`(3v_(0))/(2)`, towards left
`(3v_(0))/(2)`, towards right

Solution :(B) `T_(B)=3N " and" T_(A)=2N`
`therefore"" v_(A)=(T_(B))/(T_(A)).v_(B)=(3)/(2)v_(0)`(towards right)
`therefore"" v_(AB)=(3v_(0))/(2)-v_(0)=(v_(0))/(2),` towards right.
In such cases, velocity and acceleration are in the ration of tensions.


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