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Block of mass m is placed on frictionless slope with angle 0. Normal force acting on block due to surface will be .....

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> <br/>`(mg)/(<a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>)`<br/>`mg cos theta`<br/>`mg sin theta` </p>Solution :As <a href="https://interviewquestions.tuteehub.com/tag/shownin-1206577" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWNIN">SHOWNIN</a> figure<br/>perpendicularcomponentofweightmg thatismg cos`theta`providenormalforce N = mg cos`theta ` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C05_E05_038_S01.png" width="80%"/></body></html>


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