1.

Block of mass m is placed on frictionless slope with angle 0. Normal force acting on block due to surface will be .....

Answer»

MG
`(mg)/(COS THETA)`
`mg cos theta`
`mg sin theta`

Solution :As SHOWNIN figure
perpendicularcomponentofweightmg thatismg cos`theta`providenormalforce N = mg cos`theta `


Discussion

No Comment Found