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Blocks A and B of masses 2 kg and 1 kg respectively are pushed up a frictionless slope by a 21 N force applied parallel to the slope as shown in the figure. Find the magnitude of the force of normal reaction between A and B. [ g = 10 m/s2](A) 7 N(B) 5 N(C) 9 N(D) 3 N |
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Answer» From the figure we get that there is a backward force against the force applied that is 21N so 21-n = ma (this is because some of the force is used to start it in motion 21-n=2×7 (where m=2kg because it feels the force of 21N) [Ma=21 N (M is the total mass of the system that is 3kg) a=21÷3 a=7m/s^2] n=21-2×7 n=21-14 n=7N Whet n is normal reaction between blocks A and B Then it should be like this |
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