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Boiling point of benzene and toluene solution is 130 celsius.calculate ratio of pbenzene/ptoluene at 130 Celsius. Mole fraction of benzene in solution is 0.4 |
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Answer» Benzene and TOLUENE form an ideal SOLUTION over the ENTIRE range of composition. The vapour pressure of pure benzene and toluene at 300 K are 50.71 mm Hg and 32.06 mm Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80 g of benzene is mixed with 100 g of toluene. Explanation: NUMBER of moles is the ratio of mass to molar mass. The molar masses of benzene and toluene are 78 g/mol and 92 g/mol respectively. Number of moles of benzene =7880=1.026 Number of moles of toluene =92100=1.087 Mole fraction of benzene, XB=1.026+1.0871.026=0.486 Mole fraction of toluene, XT=1−0.486=0.514 PB=PBo×XB=50.71×0.486=24.65 mm Hg PT=PToXT=32.06×0.514=16.48 mm of Hg Total vapour pressure =24.65+16.48=41.13 mm Hg Mole fraction of benzene in vapour phase is as follows: YB=41.1324.65=0.60 |
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