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Bond angle in PH_(+)^(4) higher than in PH_(3). Why ? |
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Answer» Solution :Phosphorous in both `PH_(3)" and "PH_(4)^(+)` is `SP_(3)`hybridised. Due to the ABSENCES of lone pair - bond pair repulsion and PRESENTS of four identical bond pair - bond pair interactions. `PH_(4)^(+)` assumes tetrahedral geometry with a bond ANGLE of `109^(@) 28`' But `PH_(3)` has three bond pairs and one lone pair around P. Due to greater lone pair - bond pair repulsion than bond pair bond pair repulsion the tetra hedral angle decreases from `109^(@) 28' " to " 93.6^(@)` . As a result `PH_(3)` is pyramidal. |
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