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Bond angle in PH_(4)^(+) is higher than in PH_(3). Why? |
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Answer» Solution :Phosphorous in both `PH_(3) and PH_(4)^(+) is SP^(3)` hybridised. Due to the absence of LONE pair-bond pair repulsion and presence of four identical bond pair - bond pair interactions. `PH_(4)^(+)` assume TETRAHEDRAL geometry with a bond angle of `109^(@)28.` But `PH_(3)` has three bond pairs and one lone pair around P. Due to greater lone pair-bond pair repulsion than bond pair-bond pair repulsion. the tetrahedral angle decreases from `109^(@)28. to 93.6^(@)`.As a result PH, is pyramidal. `PH_(3)` - yramidal with bond angle of `93.^(@)` `PH_(4)^(+)` - Tetrahedral with bond angle of `109^(@)28..` |
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