1.

Bond angle of water is reduced from 109.28^(@) ot 104.5^(@).Explain.

Answer»

Solution :(i) Water molecule undergoes `sp^3` hybridisation.
The O- ATOM in `H_2O` molecule contains two bonding pairs and two lone pairs of electrons.
(iii) The overall arrangement for four electron pairs is tetrahedral but the lp-lp repulsions being greater than Ip-lb repulsions in `H_2O`
(iv) The HOH ANGLE is REDUCED to `104.5^(@)` than `109^(@)`28'
(V) The molecule has a bent shape.
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