Saved Bookmarks
| 1. |
Bond angle of water is reduced from 109.28^(@) ot 104.5^(@).Explain. |
|
Answer» Solution :(i) Water molecule undergoes `sp^3` hybridisation. The O- ATOM in `H_2O` molecule contains two bonding pairs and two lone pairs of electrons. (iii) The overall arrangement for four electron pairs is tetrahedral but the lp-lp repulsions being greater than Ip-lb repulsions in `H_2O` (iv) The HOH ANGLE is REDUCED to `104.5^(@)` than `109^(@)`28' (V) The molecule has a bent shape. (##SUR_CHE_XI_V01_C04_E03_072_S01.png" WIDTH="80%"> |
|