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Bond dissociation energy ofCH_(3)-Hbond is103Kcalmol^(-1)and0.055cal//grespectively ,If specific heat of iodine is 24cal//g at 200^(@),Calcualte its value at250^(@)C is |
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Answer» `3.61Kcalmol^(-1)` `(DeltaH_(f))_(CH_(3),H)CH_(3)-H=103` `=DeltaH_(f)(CH_(3),g)+DeltaH_(f)(H "atom, g")-DeltaH_(f)(CH_(4),g)` `(DeltaH_(f))_(CH_(3)g)=103-(103)/(2)+(-17.889)=33.611Kcalmol^(-1)` `:.` HEAT of formation of methyl radical is `DELTAH=33.611Kcalmol^(-1)` |
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