1.

Bond dissociation energy ofCH_(3)-Hbond is103Kcalmol^(-1)and0.055cal//grespectively ,If specific heat of iodine is 24cal//g at 200^(@),Calcualte its value at250^(@)C is

Answer»

`3.61Kcalmol^(-1)`
`-3.61Kcalmol^(-1)`
`33.61Kcalmol^(-1)`
`-33.61Kcalmol^(-1)`

Solution :`CH_(4)(G)=CH_(3)(g)+H("ATOM,g")`
`(DeltaH_(f))_(CH_(3),H)CH_(3)-H=103`
`=DeltaH_(f)(CH_(3),g)+DeltaH_(f)(H "atom, g")-DeltaH_(f)(CH_(4),g)`
`(DeltaH_(f))_(CH_(3)g)=103-(103)/(2)+(-17.889)=33.611Kcalmol^(-1)`
`:.` HEAT of formation of methyl radical is
`DELTAH=33.611Kcalmol^(-1)`


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