Bond energies of H_(2),Cl_(2) and HCl are respectively "104, 58 and 103 k cal mol"^(-1). Calculate Pauling's electronegativity of chlorine.

Bond energies of H_(2),Cl_(2) and HCl are respectively "104, 58 and 10

1.	Bond energies of H_(2),Cl_(2) and HCl are respectively "104, 58 and 103 k cal mol"^(-1). Calculate Pauling's electronegativity of chlorine.
Answer» Solution :AVERAGE of bond energies of `H_2` and `Cl_2` is the CALCULATED bond energy of `HCl = (104 + 58)/(2)` `= 81 K cal mol^(-1)` EXPERIMENTAL bond energy of `HCl = 100 k cal mol^(-1)` `DELTA -` Bond (resonance ) stabilisation energy = 100- 81 = 19 k cal `mol^(-1)` `X_1 - X_2 = 0.208 sqrt(Delta) = 0.208 sqrt(19)` `= 0.208 xx 4.35 = 0.90` Since Pauling.s ELECTRONEGATIVITY of hydrogen is 2.1 that of chlorine `=2.1 + 0.9 = 3.0`