Bond order of a species is 2.5 and the number of electons in its bonding molecular orbital is found to be 8 The no. of electons in its antibonding molecular orbital is

Bond order of a species is 2.5 and the number of electons in its bondi

1.	Bond order of a species is 2.5 and the number of electons in its bonding molecular orbital is found to be 8 The no. of electons in its antibonding molecular orbital is
Answer» three four equivalent orbitals at `109^(@)` 28' to each other will be formed. zero cannot be calculated FORM the given information. Solution :Bond ORDER `(1)/(2) (N_(B)-n_(a))` `2.5 = (1)/(2)(8 - n_(a)) rArr 5 = 8 - n_(a)rArr n_(a)= 8 - 5 = 3`