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Boric acid can be titrated against sodium hydroxide using methyl orange as indicator only in thepresence of polyhydroxy compound like catechol, mannitol, etc. Explain . |
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Answer» Solution :`B(OH)_(3)` reacts with `NaOH`to formsodium METABORATE. `B(OH)_(3) + NaOH rarr Na^(+) BO_(2)^(-) + 2H_(2)O` The end pointduringthe titrationof `H_(3)BO_(3)` with `NaOH`is not SHARP since `NaBO_(2)` undergoesexcessive HYDROLYSIS to give back `H_(3)BO_(3)` and `NaOH` `NaBO_(2) + 2H_(2)O hArr B(OH)_(3) + NaOH` HOWEVER,when certainpolyhydroxycompounds such as catechol, glycerol, mannitol or sugarsor any other cis-1,2,3is added totitration solution, the metaborate ION combaines withpolyhydroxy compound toform a complex. Due to formation of this complex, `BO_(2)^(-)` ion does not undergo hydrolysis. As a result, boric acid betweenas a strongmonobasicacid and the end point can thus be easily detected. |
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