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Boron has two stable isotopes, `.^(10)B(19%)` and `.^(11)B(81%)`. The atomic mass that should appear for boron in the periodic table isA. 10.8B. 10.2C. 11.2D. 10 |
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Answer» Correct Answer - A Average of atomic weight `(% of ^(10)Bxx"atoms mass of"^(10)B+%of^(11)Bxx"atomic mass of"^(11)B)/(%of^(10)B+%of^(11)B)` `=(19xx10+81xx11)/(19+81)` `=(190+891)/(100)=10.81` |
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