1.

Boron has two stable isotopes, 10B (19%) and 11B (81%). The atomic mass that should appear for boron in the periodic table is ______.(A) 10.0 (B) 10.2 (C) 10.8 (D) 11.2

Answer»

Correct option: (C) 10.8

Atomic mass = \(\cfrac{10\times 19 + 81 \times11}{100}\) 

\(\cfrac{1081}{100}\) = 10.81



Discussion

No Comment Found