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| 1. |
Boron is unable to formBF_(6)^(3-)ion. Explain. |
| Answer» Solution :Due to absence of d-orbitals, B at the maximumcan ammoundates 8 electrons pairs of electrons inits valencesshell. In otherwords, B can have a maximum convalency of 4. Therefore, `BF_(3)` can FORM`BF_(2)` but never `BF_(6)^(3-)`in whichthe COVALENCY of B is 6. | |