Boron occurs in nature in the form of two isotopes having atomic masses 10 and 11. What are the percentage abundances of these isotopes in a simple a boron having average atomic mass of 10.8 ?

Boron occurs in nature in the form of two isotopes having atomic masse

1.	Boron occurs in nature in the form of two isotopes having atomic masses 10 and 11. What are the percentage abundances of these isotopes in a simple a boron having average atomic mass of 10.8 ?
Answer» Solution :Let the PERCENTAGE abundance of B-10 ISOTOPE=X `:.` The percentage abundance of B-11 isotope = (100-x) From the available DATA : `(x xx10)/(100)+((100-x)xx11)/(100)=10.8` or `10x + 1100 - 11x = 1080or x = 20` Percentage abundance of B - 10 isotope = 20 % Percentage abundance of B - 11 isotope = 80 %.