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Boron occurs in nature in the form of two isotopes having atomic masses 10 and 11. What are the percentage abundances of these isotopes in a simple a boron having average atomic mass of 10.8 are :A. 20,80B. 80,20C. 50,50D. 40,60 |
Answer» Correct Answer - A Let the percentage abundance of B-10 isotope=x `:.` The percentage abundance of B-11 isotope = (100-x) From the available data : `(x xx10)/(100)+((100-x)xx11)/(100)=10.8` or `10x + 1100 - 11x = 1080or x = 20` Percentage abundance of B-10 isotope = 20 % Percentage abundance of B-11 isotope = 80 %. |
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